Find the height of the object after each time listed.
h = -16t^2 + 128t

(Both are different questions)

1) 1 Second

2) 4 Seconds

Question

Find the height of the object after each time listed. 
h = -16t^2 + 128t 

(Both are different questions)

1) 1 Second

2) 4 Seconds

anonymous · Answer

1) $$h=-16(1^2)+128(1)$$

anonymous · Answer

By plugging in the 1 for time, what do you think would be the answer?

anonymous · Answer

So you just plug those in?

anonymous · Answer

It's not the same answer as the book though

anonymous · Answer

Nevermind! I figured it out. I was accidentally squaring -16 into the answer

anonymous · Answer

Yes, the equation is a quadratic but it is unnecessary to solve with other methods when the variable there, is time.

anonymous · Answer

Make sure you are checking calculations and that's all!

anonymous · Answer

THANK YOU SO MUCH! :)

anonymous · Answer

You're welcome!

anonymous · Answer

Do you mind helping me with another problem

anonymous · Answer

An OBject projected from a height of 48ft with an initial velocity of 32ft per sec after t seconds has height. 

h=-16t+32t+48 

(a) after how many seconds is the height 64ft? 
(b) After how many seconds is the height 60ft? 
(c) After how many seconds does the object hit the ground? 
(d) The quadratic equation from part (c) has two solutions, yet only one of them is appropriate for answering the question. Why?