Question

1.)What is the slope of the line that passes through the points (6,4) and (3,8)?

4/3
-3/4
3/4
-4/3

2.)Select the equation of the line that passes through the point (-2.-1) and has slope 5 in point-slope form.

(y-1)=5(x-2)
(x+2)=5(y-1)
(x-2)=5(y+1)
(y+1)=5(x+2)

Answer 1

lets do 2 first
point - slope formula looks likr
\[y-y_1=m(x-x_1)\] replace \(x_1\) by \(-2\) , \(y_1\) by \(-1\) and \(m\) by \(5\)

Answer 2

and don't forget that \(y-(-1))=y+1\) etc

Answer 3

(x-2)=5(y+1)

Answer 4

no

Answer 5

(x+2)=5(y-1)

Answer 6

\[\huge y-\color{red}{y_1}=\color{blue}{m}(x-\color{green}{x_1})\]
\[\huge \color{red}{y_1}=\color{red}{-1}\\
\huge\color{blue}{m}=\color{blue}5\\
\huge \color{green}{x_1}=\color{green}{-2}\]

Answer 7

Slope of a line fixed by two points: \[points (x_1 , y_1), (x_2 , y_2) \\ y_2 -y_1 =m(x_2-x_1)\]

Answer 8

(y+1)=5(x+2)