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3x^3+7x^2-6x/6^2+14x-12 SIMPLIFY
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is the denominator 6^2 or 6x^2?
\[\frac{ 3x^3+7x^2-6x }{ 6x^2+14x-12 }\]
Whenever you're approached with equations as such, you first should see if you're able to factor out; see what they all have in common (from individual numerator then denominator). In this case, you're able to factor out an x value for the numerator, and a 2 for the denominator. \[(x(x^2+7x-6))/(2(3x^2+7x-4))\] Then, since nothing still cancels out, you should see if its possible to reduce that trinomial into 2 binomials. If you're able to (which you most likely are), cancel out anything that can be, example: (x-2)/(x/2) cancels.
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