Mathematics
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OpenStudy (anonymous):
Standard Form for Parabolas
f(x)= 2x^2 -7x + 6
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OpenStudy (anonymous):
wats ur question
OpenStudy (anonymous):
how do I put the equation into standard form
OpenStudy (anonymous):
okay
OpenStudy (anonymous):
um....can you help me?
OpenStudy (anonymous):
yes
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OpenStudy (anonymous):
thanks
OpenStudy (anonymous):
y = 2x^2 -7x+6 is the first step
OpenStudy (anonymous):
do you know what to do next
OpenStudy (anonymous):
i think its asking for factoring, because the function is already in standard form
OpenStudy (anonymous):
no I wanted to isolate 2x^2 but the other two numbers are not divisible by it
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OpenStudy (anonymous):
2
OpenStudy (anonymous):
w8 so u want to solve for x?
OpenStudy (anonymous):
no its not in standard form or known as vertex form
OpenStudy (anonymous):
and no I don't want to solve for x
OpenStudy (anonymous):
okay so u want to put it into vertex form
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OpenStudy (anonymous):
yah
OpenStudy (anonymous):
k one sec
OpenStudy (anonymous):
give me 5 mins
OpenStudy (anonymous):
alright
OpenStudy (anonymous):
okay so do uk how to complete the square?
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OpenStudy (anonymous):
you want it like (x-h)^2=4a(y-k)
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
no
OpenStudy (anonymous):
what
OpenStudy (anonymous):
f(x) =
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OpenStudy (anonymous):
f(x) = a(x-h)^2 +k this is the equation we use in class @chinenyeogueri
OpenStudy (anonymous):
ok you know y is the same thing as f(x) they are interchangable
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
hello?
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OpenStudy (anonymous):
sorry if i took too long
OpenStudy (anonymous):
standard form and vertex are the same thing....