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Mathematics 17 Online
OpenStudy (anonymous):

Standard Form for Parabolas f(x)= 2x^2 -7x + 6

OpenStudy (anonymous):

wats ur question

OpenStudy (anonymous):

how do I put the equation into standard form

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

um....can you help me?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

thanks

OpenStudy (anonymous):

y = 2x^2 -7x+6 is the first step

OpenStudy (anonymous):

do you know what to do next

OpenStudy (anonymous):

i think its asking for factoring, because the function is already in standard form

OpenStudy (anonymous):

no I wanted to isolate 2x^2 but the other two numbers are not divisible by it

OpenStudy (anonymous):

2

OpenStudy (anonymous):

w8 so u want to solve for x?

OpenStudy (anonymous):

no its not in standard form or known as vertex form

OpenStudy (anonymous):

and no I don't want to solve for x

OpenStudy (anonymous):

okay so u want to put it into vertex form

OpenStudy (anonymous):

yah

OpenStudy (anonymous):

k one sec

OpenStudy (anonymous):

give me 5 mins

OpenStudy (anonymous):

alright

OpenStudy (anonymous):

okay so do uk how to complete the square?

OpenStudy (anonymous):

you want it like (x-h)^2=4a(y-k)

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

no

OpenStudy (anonymous):

what

OpenStudy (anonymous):

f(x) =

OpenStudy (anonymous):

f(x) = a(x-h)^2 +k this is the equation we use in class @chinenyeogueri

OpenStudy (anonymous):

ok you know y is the same thing as f(x) they are interchangable

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

hello?

OpenStudy (anonymous):

okay this way to long so im just gonna tell to go to this video http://www.youtube.com/watch?v=dse3XdN9q2k it tell you how to convert standard form to vertex

OpenStudy (anonymous):

sorry if i took too long

OpenStudy (anonymous):

standard form and vertex are the same thing....

OpenStudy (kc_kennylau):

http://www.mathwarehouse.com/geometry/parabola/images/standard-vertex-forms.png @lovelike_woee it's already in standard form...

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