Question

How do I do this?

Answer 1

For H, you need this theorem:

Answer 2

thanks! :)

Answer 3

What is the measure of the red arc on the attachment.

Answer 4

Together, the red arc and the blue arc are the entire 360 so the arcs add up to 360.

Answer 5

so just have to subtract it from 360 right?

Answer 6

Yes.

Answer 7

360 - 220 = ?

Answer 8

140.
so..
PR = 140
<S = 40
?

Answer 9

Yes. m<S = 40.

Answer 10

Do the same kind of procedure for #2.

Answer 11

If arc PTR = b, what is the measure of the rest of the circle?

Answer 12

can it be 360-b?

Answer 13

Correct.

Answer 14

M<S = 1/2 * ( b - (360 - b) )

M<S = ?

Answer 15

[b - (360 - b)] / 2

Answer 16

can it still be reduced?

Answer 17

yes

Answer 18

1/2 * ( b - (360 - b) ) =

1/2 * ( b - 360 + b) =

Answer 19

360 / 2
180?

Answer 20

1/2 * ( b - 360 + b) =

1/2 * ( 2b - 360) =

1/2 *2b - 1/2 * 360 = ?

Answer 21

1/2 *2b - 1/2 * 360 =

b - 180 = m<S

Answer 22

thanks :)

Answer 23

Did you get arc PR as 360 - b

Answer 24

yes c:

Answer 25

For I, this theorem

Answer 26

I. 1 is correct

Answer 27

I.2 is correct

Answer 28

yay c:

Answer 29

3a/4 = 1/2 * (m arc AC - a)

2 * (3a/4) = 2* (1/2) * (m arc AC - a)

Answer 30

3a/2 = (m arc AC - a)

Answer 31

3a/2 + a = m arc AC

3a/2 +2a/2 = m arc AC

5a/2 = m arc AC

Answer 32

oh really let me try.

Answer 33

Please do because what I got does not look right. I'm checking it now.

Answer 34

I think.. \[\frac{ 6a }{ 8 }+ a\]
will do so too, right?

Answer 35

since if you subtract it with a..
it'll be 6a/8
and divided by 2..
3a/4
:))

Answer 36

Yes, but you should write 6a/8 + a in a simplified form.

If the answer to a problem is 7, a person does not write the answer as (5 + 2) even though that is correct.

Answer 37

I do not think 6a/8 + a is correct. It equals 6a/8 + 8a/8 = 14a/8 = 7a/8 which is not 5a/2, the correct answer.

Answer 38

Would you like me to demonstrate that 5a/2 is correct?

Answer 39

oh. see.
yes please?

Answer 40

1/2 * ( 5a/2 - a) =

1/2 ( 5a/2 - 2a/2) =

1/2 (3a/2) =

3a/4

which is the given measure of <B

Answer 41

So, m arc AC = 5a/2

Answer 42

oh, right..
*applause*
so smart ._.

Answer 43

Not really.

Answer 44

What about I.4 ?

Answer 45

I4, I made it up.. I'm not so sure but yeah..

Answer 46

90 = 1/2* (m arc AC - m arc DE)

90 = 1/2 * (m arc AC - (90 + a ) )

Answer 47

Multiply both sides by 2

180 = (m arc AC - (90 + a ) )

Answer 48

180 = m arc AC - 90 - a

Answer 49

180 = m arc AC - 90 - a
+ 90 + a + 90 + a
-----------------------------------------

(270 + a) = m arc AC

Answer 50

mine was (270 + 3a)
..almost .. :|

Answer 51

I'm getting sleepy. Maybe I should check yours.

Answer 52

Oh, sorry for troubling you.
You should get to sleep now :)

Answer 53

No, not when there are points to lose. There is an "a" missing in this answer. Let's find it.

Answer 54

Here's the error.

I put the wrong value in for the measure of <B.

Answer 55

90 - a = 1/2* (m arc AC - m arc DE)

Answer 56

Hmm, thank you so much.
Oh.. "+a"
right..

Answer 57

90 - a = 1/2 * (m arc AC - (90 + a ) )

2* (90 - a) = (m arc AC - (90 + a ) )

Answer 58

180 - 2a = m arc AC - 90 - a

Answer 59

180 - 2a = m arc AC - 90 - a
+90 + a + 90 + a
-------------------------------------

270 - a = m arc AC

Answer 60

We should check that. :)

Answer 61

will do so :)

Answer 62

I see no errors

Answer 63

1/2 * ( 270 - a - (90 + a) ) =

1/2 * (270 - a - 90 - a) =

1/2 * ( 180 - 2a) =

Answer 64

90 - a for m < B. That is what was given.

Answer 65

right. yesss :)

Answer 66

That is an Algebra work-out exercise.

Answer 67

yeah, which i hate the most xD

Answer 68

Algebra cannot be escaped. :)

Answer 69

that's right.. x(

Answer 70

Alrighty, then.

Answer 71

why don't you go to sleep now? you're probably tired

Answer 72

I thought you had more problems but were sleepy yourself.

Answer 73

yeah.. but you need sleep. haha

Answer 74

You're the one who wrote this: directrix: i'm doing both since its almost sleep time :|

Answer 75

that's right.. I got no choice x|

Answer 76

If you want to do another problem now, just post it.

Answer 77

Post it in a new thread, though.

Answer 78

Alright but I think this should be the last