Question

Shiloh has to earn at least $200 to meet her fundraising goal. She has only 100 cakes that she plans to sell at 5 dollars each. Which inequality shows the number of cakes, x, Shiloh can sell to meet her goal?

20 ≤ x ≤ 200

40 ≤ x ≤ 100

100 ≤ x ≤ 200

20 ≤ x ≤ 100

Answer 1

@Brent0423 can ya help me with this question?

Answer 2

What have you tried so far?

Answer 3

and yes i can!

Answer 4

which is the best answer? c:

Answer 5

what times $5 =$200 ??

Answer 6

@shoeless what do you think the best answer would be?

Answer 7

We know that Shiloh can only sell a maximum of 100 cakes, so the 1st and 3rd choices are ruled out. Shiloh wants to sell AT LEAST x # of cakes to meet her $200 goal. Given that her earnings from selling x # of cakes is (price) x (#of cakes sold) = 5x, then solve:
5x is greater than or equal to 200 (since she wants AT LEAST $200).

Answer 8

Solving that inequality gives us x must be greater than or equal to 40. So I would think the answer is: 40 ≤ x ≤ 100

Answer 9

Good work Shoeless!

Answer 10

thank you :] do you think you can help with one more?

Answer 11

@shoeless

Answer 12

Solve for x.

-ax + 4b > 9

x > the quantity negative 3 times b minus 5 all over negative a

x < the quantity 5 minus 3 times b all over negative a

x < the quantity negative 3 times b plus 5 all over negative a

x > the quantity negative 3 times b plus 5 all over negative a

Answer 13

-ax + 4b > 9, subtract 9 from both sides and add ax to both sides
4b - 9 > ax, divide both sides by a
(4b - 9)/a > x

Answer 14

I don't know where the 3 and the 5 come from in the options you were given. hmmm. That's how I would solve for x.

Answer 15

so which is the best answer?

Answer 16

@shoeless