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Mathematics 11 Online
OpenStudy (anonymous):

Help 5 questions discontinuities of rational expressions

OpenStudy (anonymous):

OpenStudy (anonymous):

@Luigi0210 ? :)

OpenStudy (luigi0210):

Sorrry, I don't wanna answer that many questions >.<

OpenStudy (anonymous):

@Luigi0210 please :(

OpenStudy (anonymous):

@Compassionate

OpenStudy (luigi0210):

When you find zeros, for the first one, it means set x=0 and simplify. So do that to the first one and tell me what you get

OpenStudy (anonymous):

c? x=9? or x=-9

OpenStudy (luigi0210):

Wait, nvm, I think it's just asking to factor the top.. so if that's right: x(4x-36)=0 x=0 4x-36=0 ------------------- x=36/4=9 ------------------ So x=0, and 9

OpenStudy (anonymous):

okay #2

OpenStudy (luigi0210):

Just factor the top, and what do you get?

OpenStudy (anonymous):

(x+4)(x-7)

OpenStudy (anonymous):

x+4 can cel and im left with x-7

OpenStudy (luigi0210):

Correct, so there's a hole at x=4 (4, y) To find what y is, plug 4 back into x-7

OpenStudy (anonymous):

-3 c

OpenStudy (luigi0210):

Correct

OpenStudy (anonymous):

#3

OpenStudy (luigi0210):

Factor first

OpenStudy (anonymous):

(2x-3) (x+4) ----------- (x+4)

OpenStudy (luigi0210):

Correct, and we have a hole, can you identify where it's at?

OpenStudy (anonymous):

isk :(

OpenStudy (luigi0210):

Well, we know it's at x=4, and both C and D have the same (4, 5) meaning it's that, now we just need to find zeros. So solve for x at 2x-3=0.

OpenStudy (anonymous):

how do i solve 2x-3=0 like this? |dw:1386720764156:dw|

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