Pretty sure I am over thinking this question! Help please :) Given the function f(x) = x + 3x + 4 , find the value of f(–1).
f(–1) = 8
f(–1) = –2
f(–1) = 0
f(–1) = 2

Question

Pretty sure I am over thinking this question! Help please :) Given the function f(x) = x + 3x + 4  , find the value of  f(–1). 
       f(–1) = 8
       f(–1) = –2
       f(–1) = 0
       f(–1) = 2

anonymous · Answer

$$f(-1)=-1-3+4=0$$...assuming you didn't mean $$f(x)=x^2+3x+4$$

ddcamp · Answer

Just replace each x with (-1):
f(-1) = (-1) + 3(-1) + 4
f(-1) = -1 - 3 + 4
f(-1) = 0

anonymous · Answer

i assume this is 
$$f(x)=x^2+3x+4$$ think of it as 
$$f(\diamondsuit)=\diamondsuit ^2+3\times \diamondsuit +4$$

anonymous · Answer

replace $\diamondsuit$ by $-1)$ with judicious use of parentheses and compute 
$$f(-1)=(-1)^2+3\times (-1)+4$$

anonymous · Answer

thanks a bunch guys :)