Solve for x 3x+3y=15 3x+2y=13 Medal and Fan!!
@phi
\[3x+3y=15\] \[3(x+y)=15\] \[x+y=5\] ??
????
i dont get it!!!!!
i'd say, try subtracting the 2nd equation from the 1st equation, what u get ?
Okay so i at least know that you have to solve for x in the first equation then substitute x for the second equation. But i dont know how to do that!!
thats substitution method what i suggested was elimination method if you are more comfortable with substitution method, you know you need to solve for x have you tried, which step are u stuck ?
i just dont know how to solve for x in the first equation
start by factoring out 3 from left side 3x + 3y = 3 (...?..)
x=3
would i subtract 3 from both sides???
im confused!!!!!!!!!!!!!!!!!!!!!!!!!!!
When you see 3x+3y=15 3x+2y=13 you should notice that 3x - 3x is 0 (and the x's go away) if you subtract the top equation minus the bottom equation, you will get a new (improved!) equation with only a y. solve for y, then use that value in either of the original equations to find x.
(3x+3y=15) multiply by 2 (3x+2y=13) multiply by -3 result: 6x+6y=30 -9x-6y=-39 add the two equation using elimination method -3x=-9 x=3
subract an equation means: multiply every term in the bottom equation by -1, then add term by term to the top equation
mine is a bit more complex than @phi... :D
y=2?
correct
Now use y=2 to find x
just substitute it to any of the 2 given eqation and you get x. :)
x=3?
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