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Why does integral 1/(x^2+4) = 1/2 arctan (x/2) + C ?
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Why does\[\int\limits_{}^{}\frac{ 1 }{ x ^{2} + 4 } = \frac{ 1 }{ 2 }\arctan(\frac{ x }{ 2 })+C\]
I know that \[\int\limits_{}^{}\frac{ 1 }{x ^{2} +1 } = \arctan(x)\] But I cant seem to figure out why the above is true
Magic, what else? ^.^
pfff \[\Large \int \frac{1}{x^2+4}dx=\int \frac{1}{4\left(\frac{x^2}{4}+1\right)}dx=\frac14\int \frac{1}{\frac{x^2}{4}+1}dx\]
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