Please help me
How to find the recursive formula for 5,10, 20, 40...
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OpenStudy (waheguru):
The general equation is
t(n) = t(n-1)+d
jimthompson5910 (jim_thompson5910):
you're using the wrong recursive general equation
you should be using this
t(n) = r*t(n-1)
where t(n) is the nth term, r is the common ratio, and t(n-1) is the term before the nth term
OpenStudy (waheguru):
Would this be correct then?
t(n) = t(n-1)*2 ?
jimthompson5910 (jim_thompson5910):
or
t(n) = 2*t(n-1)
good
OpenStudy (waheguru):
Thanks and what about the general term formula?
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jimthompson5910 (jim_thompson5910):
well this is a geometric sequence with first term a = 5, common ratio r = 2
jimthompson5910 (jim_thompson5910):
so you tell me
OpenStudy (waheguru):
t(n) = 5 + something?
jimthompson5910 (jim_thompson5910):
no
jimthompson5910 (jim_thompson5910):
the nth term of a geometric sequence is found by
t(n) = a*r^(n-1)
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OpenStudy (waheguru):
What does r stand for?
jimthompson5910 (jim_thompson5910):
r is the common ratio
jimthompson5910 (jim_thompson5910):
to find the next term, you multiply by the common ratio
OpenStudy (waheguru):
Ok, so I got
t = 5*2(n-1)
OpenStudy (waheguru):
I understand this know, i appreciate your help alot
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jimthompson5910 (jim_thompson5910):
more like
\[\Large t(n) = 5*2^{n-1}\]
but I think that's what you meant to say