can someone explain to me how to factor each expression without x-boxing it I'd like to learn another faster way I have 72 problems and all I know is x-box???????????

Question

anonymous · Answer

@Hero  @Lena772   @Luigi0210   @tHe_FiZiCx99    @mathmale @Mel98

lena772 · Answer

http://www.mathsisfun.com/algebra/factoring.html check this

the_fizicx99 · Answer

It's a faster method. Need alot of paper though. Looks like a Christmas tree lol. http://amby.com/educate/math/images/factor-tree_96.gif

anonymous · Answer

lol, thanks guys

anonymous · Answer

what the monkey is "x box" other than the obvious xmas present?

hero · Answer

For any quadratic polynomial of the form $ax^2 + bx + c$, Find two numbers that multiply to get $ac$ yet add to get $b$

For example:

$x^2 - 16x - 36$

Notice that $ac = -36$ and $b = -16$. We need to find two numbers that multiply to get $-36$ yet add to get $-16$. The only two numbers that work are $-18$ and $2$ since $-18 \times 2 = -36$ and $-18 + 2 = -16$

Knowing this we can factor as follows:

$x^2 - 16x - 36$
$x^2 -18x + 2x - 36$
$x(x - 18) + 2(x - 18)$
$(x - 18)(x + 2)$