Question

Please help!
Solve the system of equations:
2x-5y=3
x-3y=1

Answer 1

do you prefer substitution or elimination ?

Answer 2

I know substitution best.

Answer 3

x - 3y = 1 ---> x = 3y + 1
now sub 3y + 1 in for x in the other equation

2x - 5y = 3
2(3y + 1) - 5y = 3
do you know how to finish and find y ?

Answer 4

No. :/

Answer 5

2(3y + 1) - 5y = 3 -- distribute through the parenthesis
6y + 2 - 5y = 3 -- subtract 2 from each side
6y - 5y = 3 - 2 -- combine like terms
-y = 1 -- multiply by -1 to make y positive
y = -1
now sub -1 in for y in either of the original equations
x - 3y = 1
x - 3(-1) = 1
x + 3 = 1 -- subtract 3 from both sides
x = 1 - 3
x = -2

check..
x - 3y = 1
-2 - 3(-1) = 1
-2 + 3 = 1
1 = 1 (correct)

x = -1 and y = -2 or (-1,-2)

Answer 6

oops..x = -2 and y = -1

Answer 7

Okay, so would that be the answer? Because I have these choices:
(4, 1)
(5, 2)
(7, 2)
(9, 3)

Answer 8

hmmm.....let me try something different...hold on

Answer 9

2x - 5y = 3
x - 3y = 1 --->(-2)
--------------
2x - 5y = 3
-2x + 6y = -2 (result of multiplying by -2)
-------------add
y = 1
now sub 1 in for y
x - 3y = 1
x - 3(1) = 1
x - 3 = 1
x = 1 + 3
x = 4

I must have made a mistake on the substitution....elimination method gave me (4,1)

Answer 10

Okay. Thank you so much! ^-^ Do you think you could possibly help me with 2 more questions?

Answer 11

not right now..I have to go do something...I will be on later...sorry :(

Answer 12

Okay. Adios.