Question

determine the equcation whose roots are -3, -3, and 3
a) x^3+3x^2-9x-27=0
b) x^3-9x^2+27x+8=0
c)x^3-3x^2+9x=0
d)x^3-3x^2+8x=0

Answer 1

if the roots are -3, -3, and 3. the roots can also be read as the zeros to an equation.
then, we can set it up as:
(x+3)(x+3)(x-3)
then foil it to get an equation

Answer 2

@DemolisionWolf which one is it??

Answer 3

you need to FOIL this:
(x+3)(x+3)(x-3)

Answer 4

i forget how to foil when their is 3 of them

Answer 5

ok,
first just FOIL two of them to start out

Answer 6

(x^2+6x+9) (x-3)

Answer 7

good!
can you now FOIL what you have again?

Answer 8

like this: