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OpenStudy (anonymous):
Plz help!!!
Given the equation y = x2 – 4x + 3.
Convert to vertex form. Show all work
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OpenStudy (kc_kennylau):
What's the coefficient of the middle term? :)
OpenStudy (kc_kennylau):
Divide it by 2 and square that
OpenStudy (kc_kennylau):
\[y=x^2-4x+3\\y=x^2-4x+4-1\\y=(x-2)^2-1\]
OpenStudy (anonymous):
okay thanks
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OpenStudy (kc_kennylau):
no problem :)
OpenStudy (anonymous):
how would you find the vertex from that???
OpenStudy (anonymous):
@kc_kennylau
OpenStudy (kc_kennylau):
\[y=(x-2)^2-1\\\therefore V=(2,-1)\]
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OpenStudy (anonymous):
oh, I see.
OpenStudy (anonymous):
would I have to graph it to find the line of symmetry?
OpenStudy (kc_kennylau):
don't think so :)
OpenStudy (kc_kennylau):
\[\because V=(2,-1)\\\therefore \mbox{Eqn of L}_\mbox A:\hspace{4pt}x=2\]
OpenStudy (kc_kennylau):
PostScript: Don't follow my presentation
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OpenStudy (anonymous):
k...
OpenStudy (anonymous):
how would I "state the zeros"???
OpenStudy (kc_kennylau):
Zeros occur when y=0
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