given the binomials (x-2),(x-1),(x+2) and (x-4), which one is a factor of f(x)=3x^3-12x^2-4x-55?
ok i got (x-2) is that right?
@kc_kennylau
does f(2) = 0?
oh no. but (+4) does
3x^3-12x^2-4x -55 0 6 -12 32 2 3 -6 -16 not0 yeah, a run of syntheticD says 2 is bad 3x^3-12x^2-4x -55 0 12 0 -16 4 3 0 -4 not0 i dont htink 4 is a good fit either
3x^3-12x^2-4x -55 0 3 -9 -13 1 3 -9 -13 not0 lol, i seems to be out as well
im going to try (x-1)
i think that works!
last one better be it .. 3x^3-12x^2-4x -55 0 -6 36 -64 -2 3 -18 32 not0 ugh, i need more sythD practice ....
Well in fact none of them works, but you can keep trying :)
http://www.wolframalpha.com/input/?t=crmtb01&f=ob&i=factorize%203x%5E3-12x%5E2-4x-55
i see that lol
i was assuming one of them was right arg
what about (x-5)?
im going to try
x-5 fits, but that wasnt an option you gave us .... so the good news is i dont need synthD practice afterall :)
lol thnk you!!
Join our real-time social learning platform and learn together with your friends!