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Mathematics 16 Online
OpenStudy (anonymous):

given the binomials (x-2),(x-1),(x+2) and (x-4), which one is a factor of f(x)=3x^3-12x^2-4x-55?

OpenStudy (kc_kennylau):

http://img.docstoccdn.com/thumb/orig/106604345.png

OpenStudy (anonymous):

ok i got (x-2) is that right?

OpenStudy (anonymous):

@kc_kennylau

OpenStudy (amistre64):

does f(2) = 0?

OpenStudy (anonymous):

oh no. but (+4) does

OpenStudy (amistre64):

3x^3-12x^2-4x -55 0 6 -12 32 2 3 -6 -16 not0 yeah, a run of syntheticD says 2 is bad 3x^3-12x^2-4x -55 0 12 0 -16 4 3 0 -4 not0 i dont htink 4 is a good fit either

OpenStudy (amistre64):

3x^3-12x^2-4x -55 0 3 -9 -13 1 3 -9 -13 not0 lol, i seems to be out as well

OpenStudy (anonymous):

im going to try (x-1)

OpenStudy (anonymous):

i think that works!

OpenStudy (amistre64):

last one better be it .. 3x^3-12x^2-4x -55 0 -6 36 -64 -2 3 -18 32 not0 ugh, i need more sythD practice ....

OpenStudy (kc_kennylau):

Well in fact none of them works, but you can keep trying :)

OpenStudy (amistre64):

i see that lol

OpenStudy (amistre64):

i was assuming one of them was right arg

OpenStudy (anonymous):

what about (x-5)?

OpenStudy (anonymous):

im going to try

OpenStudy (amistre64):

x-5 fits, but that wasnt an option you gave us .... so the good news is i dont need synthD practice afterall :)

OpenStudy (anonymous):

lol thnk you!!

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