Which of the following ordered pairs is a solution to the system of linear equations below? Three x plus y equals nine. Two x minus two y equals fourteen. (2, 3) (3, 2) Four, negative three. Negative three, four.
3x+y=9 2x-2y=14 write it out so it is easier to visualize
Didn't you solve a 3 variable system of equations? Anyways, 3x + y = 9 2x - 2y = 14 3x *(-2) + y*(-2) = 9*(-2) 2x*(3) -y*(3) = 14*3 -6x -2y = -18 6x -6y = 42 0 -8y = 24 /-8 /-8 y = -3 Now you solve for X. Plug in Y.
3x+y=9 2x-2y=14
Can you do it? If you want I can guide you along it. :)
I'm confused :)
Sorry, k. So when you plug in Y for your first equation you should get. 3x + (-3) = 9 A positive and a negative = negative So this is: 3x -3 = 9 add 3 to both sides to leave x alone on the left.
x=4 right?
Yup!! So now plug in x and y and it should give you 9 = 9 When it does those are your coordinates!!
Where do i plug in what?
xD you keep changing your picture lol um plug in x and y 3(4) + (-3) = 9
*proves
Fake?
I said It proves I'm not fake
Cause alot of people say im too pretty to be real lol
That means 2 things lol xDDD and yea, um 3*4 - 3 = 9 3*4 = 12 12 - 3 = 3 12-3 = 9 9 = 9 Solution!! It works. You plug it in for the other equation and see if its true
12 - 3 = 9 *
The solution works right?
Then does are your coordinates. (4,-3)
Yes lol, did you plug it in to see if it works for the other equation? Cx It's (4,-3) I can see its 14 = 14 just by looking at it
Did you understand though? It's pointless for me to do your work if you don't understand, you'll just be lost during your exam... take it from experience <- :$ :)
@TTP did you understand :D
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