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Find f if f'(x)= 2t-3sin(t) and f(0)= 5.
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Start by integrating f'.
is f(t)=t^2+3cos(t) ?
And a constant.
no its that plus a constant C to evaluate C substitute x = 0 and f(0) = 5
would the answer be f(t)=t^2+3cos(t)+2
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How did you get that?
i plugged 0 for x and ended up with 3 but to get 5, since f(0)=5 I made the C=2, but I dont know if im right
You're very right.
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