What are the real or imaginary solutions of the polynomial equation? 27x^3 + 125 = 0
@Luigi0210 i know ur probably tired of explaining these things to me but could u help me again? like do i just factor this as well?
Starts by getting x by itself.
27x^3 + 125 = 0 Divide both sides by 27 x^3 + 4.6296296296 =0
so far i have 27x^3+125=0 then i subtracted 125 from each side which gives me 27x^3= -125 after that i divided each side by 27 so now i have x^3= -4.63 so now what do i do?
Take the cube root of -4.63
Ah, there's both of your guy's mistakes. When you divide, don't simplify it into a decimal, just leave it as a fraction.
So you'll have: \[\LARGE -\frac{125}{27}\] Now take the cubic root of each: \[\LARGE -\frac{5}{3}\]
so x would equal -5/3?
Yup, when you take a cubic root, anything that isn't even, you are allowed to take the negative root of it.
Well I used a calculator to determine the cube root of -4.6296296296 and it's -1.6666666667 and -5/3 = -1.6666666666666666
Yea, both methods work, but leaving it in fractions will give you a precise answer, while decimals are just an approximation.
ok so when it says What are the real or imaginary solutions of the polynomial equation? all i have to do is say that the answer is i 5/3 ? or 5/3i or i(5/3)
no the answer is actually -5/3
Yea, you only get imaginary answers when it is squared and it has a negative.
So it's -5/3
You can take a cube root of a negative number.
ohh ok its slowly making sense now :) thanks guys ^_^
u r welcome :-)
Anytime Alleyyyy
oh quick question do you know how to take the cubic root on a TI-84 calc?
I don't know if it has the cube root function. But look for a key that looks like this |dw:1386981945266:dw|
|dw:1386982095251:dw|
The Ti-84 does actually have that function, I just need to find mine.
Okay that's just square root - NOT what you need. Look for a key that looks like this |dw:1386982190585:dw|
wolf this is what my calc looks like the gray one. on the right
Screw it, I can't find it. Just use the exponential function. Make sure to use the parenthesizes
ok maybe i will google it :\ i have 2 more question mind helping?
Heck - okay
i tagged you in it :)
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