Please help!!!

1.Simplify.
5x+1=2x+7

2.simplify.
7x+3=5-2x

Which equation has infinity many solution? Please show your work.
A.3x-5=3(5+x)
B.(x+3)=3(x+5)
C.3x-5=3(5-x)
D.(x+3)=-5(3-x)

Question

Please help!!!



1.Simplify.
5x+1=2x+7

2.simplify.
7x+3=5-2x

Which equation has infinity many solution? Please show your work.
A.3x-5=3(5+x)
B.(x+3)=3(x+5)
C.3x-5=3(5-x)
D.(x+3)=-5(3-x)

crazycocob · Answer

I give medals!

anonymous · Answer

1). x = 2

jigglypuff314 · Answer

5x + 1 = 2x + 7
subtract 2x from both sides
subtract 1 from both sides
divide both sides by 3

7x + 3 = 5 - 2x
add 2x to both sides
subtract 3 from both sides
divide both sides by 9 and simplify

jigglypuff314 · Answer

the last one seems a bit odd...
the way you would solve it would be solving for all options
so for example 3x - 5 = 3(5 + x)
distribute so     3x - 5 = 15 + 3x    then subtract both sides by 3x
                     -3x                 -3x
but then you're left with   -5 = 15
but negative 5 does not equal 15
therefore A would be considered "no solution"

to get "infinitely many solutions"  
you would have to end up with something like   5 = 5