Question

can someone tell me the rest of these tan cos sin theta

Answer 1

elaborate the question.

Answer 2

secant cosecant and cotangent? is that what your wanting?

Answer 3

Sine, cosine, and tangent. Their inverses are (respectively) Cosecant, secant, and cotangent.

Answer 4

Did you want the identities? Hope this helps you then.

http://www.purplemath.com/modules/idents.htm


I got some other interesting staff for you.
\[\color{blue} {Sin~x} \color{red} {=} \color{blue} {\sqrt{1-Cos^2x}}~~~~~~~~~and\]\[\color{blue} {Cos~x} \color{red} {=} \color{blue} {\sqrt{1-Sin^2x}}\]
being that \[\color{green} {Sin~^2x} \color{red} {=} \color{green} {1-Cos^2x}~~~~~and\]\[\color{green} {Cos~^2x} \color{red} {=} \color{green} {1-Sin^2x}\]
Ask anytime, I can tell you more....

Answer 5

nevermind but thank you i was asking fro like but someone helped me

Answer 6

like sin=opp/hyp cos=adj/hyp

Answer 7

\[\huge\color{blue}{\huge {\bbox[5pt,cyan,border:2px solid purple]{SOH~~~~CAH~~~~TOA}}}\]

Answer 8

i have that now thank you

Answer 9

Yeah, what class are you taking Geometry?

Answer 10

trig

Answer 11

Oh I see, I just learned this in Geometry, ...whatever, the main thing is that you have this now, it's useful.

Answer 12

can you help me in a word problem

Answer 13

I can try, I'm not really good at math.

Answer 14

sara places a ladder on level ground against a vertical wall.when the base of the ladder is 20ft from the wall,the ladder reaches a height of 15ft along the wall.sara then moves the base 7ft closer to the wall. to the nearset foot,how high up the wall does the ladder now reach

Answer 15

(esp word problems)

Answer 16

sure @praxer

Answer 17

\[\sqrt{13^2+15^2}=?\]

Answer 18

Do you see what I am doing or I am going too fast?

Answer 19

i see

Answer 20

\[\sqrt{394}~~≈~~19.85\]

Answer 21

weere did u get that

Answer 22

got what?\[13^2+15^2=394~~~~~~~~~~~~~PATHEGORIAN\]\[\sqrt{13^2+15^2}=\sqrt{394}~≈~19.85\]