Question

write the following equation in slope-intercept form...
6x+9y=27
medals will be awarded to first best answer

Answer 1

Slope-intercept form is y = mx + b
So we just basically get y = whatever it ends up being

6x+9y=27
Move over the x, by subtracting 6x from both sides.

9y = 27 - 6x
Now let's divide it all by 9 and re-arrange

y = -2/3 x + 3

Answer 2

seems pretty good but im still confused medal was awarded further explaining will result in me being a fan @G-unit

Answer 3

step by step i think would clarify things

Answer 4

Okay, so you're given an equation, that has x's, y's, and numbers. The point slope form is

y = mx + b

Y stands for Y, or 1Y.
m stands for the slope, X stands for X, and b stands for the intercept.

None of that matters though, in this question. We just have to make sure we end up having Y as Y, and nothing else. That means we can't leave it as 9Y.

So let's start again, and this time divide everything by 9 first.

9Y divided by 9 is Y
6X divided by 9 is 6x/9, which we can simplify to 2X/3 by dividing both top and bottom by 3, right?
Then 27 divided by 9 is 3.


Now let's re-visualize it

2X/3 + Y = 3

Let's get the Y on the left side by itself now. We'll just subtract the whole X part to the other side.
-2X/3 on both sides.

We get

Y = -(2X/3) + 3

We can rewrite the X bit as...

-2/3 X


So now we have

Y = -2/3 X + 3

Answer 5

By the way, it would be (-2/3)x and not (-2)/(3x)

So it would look like

\[\frac{ 2 }{ 3 } x\]

Answer 6

thank you very much!!! greatly appreciated nice @G-unit