Can some one help me with these two problems?
1. sqrt(64m^4r^12)
2. sqrt(200x^8y^15)

Question

Can some one help me with these two problems?
1. sqrt(64m^4r^12)
2. sqrt(200x^8y^15)

anonymous · Answer

$$\sqrt{64m ^{4}r ^{12}}$$
What times itself will give you 64?

anonymous · Answer

Perfect squares include 
1*1=1
2*2=4
3*3=9
4*4=16
5*5=25 and so on

anonymous · Answer

I know it's 8m^2 but what about the r^12?
Does it turn into 3 & 4 or 3 6 and 2 ?
I got confused, and I don't know what to do what to do after.

anonymous · Answer

3 and 6*

anonymous · Answer

take the 12 and divide by 2
you get 8m^2r^6

anonymous · Answer

finding the square roots of exponents under the sign, divide by 2

anonymous · Answer

So I don't have to divide the 6?

anonymous · Answer

i don't think so

anonymous · Answer

Thanks for the help.

anonymous · Answer

sqrt(200x^8y^15)
200 isn't a perfect square--but you can take 100*2 and find the sq rt of 100

anonymous · Answer

$$\sqrt{200x ^{8}y ^{15}}$$
$$10x ^{4}y ^{7}\sqrt{2y}$$