Question

Can some one help me with these two problems?
1. sqrt(64m^4r^12)
2. sqrt(200x^8y^15)

Answer 1

\[\sqrt{64m ^{4}r ^{12}}\]
What times itself will give you 64?

Answer 2

Perfect squares include
1*1=1
2*2=4
3*3=9
4*4=16
5*5=25 and so on

Answer 3

I know it's 8m^2 but what about the r^12?
Does it turn into 3 & 4 or 3 6 and 2 ?
I got confused, and I don't know what to do what to do after.

Answer 4

3 and 6*

Answer 5

take the 12 and divide by 2
you get 8m^2r^6

Answer 6

finding the square roots of exponents under the sign, divide by 2

Answer 7

So I don't have to divide the 6?

Answer 8

i don't think so

Answer 9

Thanks for the help.

Answer 10

sqrt(200x^8y^15)
200 isn't a perfect square--but you can take 100*2 and find the sq rt of 100

Answer 11

\[\sqrt{200x ^{8}y ^{15}}\]
\[10x ^{4}y ^{7}\sqrt{2y}\]