Verify that quadrilateral BCDE is a rhombus with vertices B(-5, 1), C(0, 6), D(5, 1) and E (0, -4) by showing that all four sides are equal.
A. BD = CE = square root of 50
B. BD = CE = 50
C. BC = CD = DE = EB = 50
D. BC = CD = DE = EB = square root of 50

Question

Verify that quadrilateral BCDE is a rhombus with vertices B(-5, 1), C(0, 6), D(5, 1) and E (0, -4) by showing that all four sides are equal.
	A.	BD = CE = square root of 50
	B.	BD = CE = 50
	C.	BC = CD = DE = EB = 50
	D.	BC = CD = DE = EB = square root of 50

anonymous · Answer

please help this is my last question and i really need help     best answer gets a medal

anonymous · Answer

b?

anonymous · Answer

D, the lengths are found from square root of the sum of the squares of the x difference and the y differences, so

BC=sqrt[(5-0)^2 + (1=6)^2] = sqrt(50) etc.