Question

what is the equation in standard form of a perpendicular line that passes through (5,1) the equation they gave me to answer the question is y-3=3(x+1)

Answer 1

First find the slope of the line: y-3=3(x+1)
Can you find the slope?

Answer 2

the slope is 3

Answer 3

Yes. The slope of the perpendicular line will be the negative reciprocal of this slope.

Answer 4

what is the negative reciprocal of the slope

Answer 5

Slope of the perpendicular line = -1/3
Equation of a line in slope-intercept form is: y = mx + b
m = -1/3
y = -1/3x + b
It passes through (5,1).
Put x = 5, y = 1 into the equation and solve for b.
Then put the equation in the standard form.

Answer 6

so is this how the answer's suppose to be 1=-1/3*5+b (* means multiply)

Answer 7

solve for b.

Answer 8

1 = -5/3 + b
b = 1 + 5/3 = 8/3
y = -1/3x + 8/3 (this is the equation in slope-intercept form).
They want the equation in standard form:
multiply throughout by 3
3y = -x + 8
x + 3y = 8 is the equation of the perpendicular line in standard form.

Answer 9

thank you : D

Answer 10

what is the intercept of the perpendicular line this is right after the first question Ist asked

Answer 11

The y-intercept is the value for "b" we found earlier: 8/3

In y = mx + b, m is the slope and b is the y-intercept.

Answer 12

what the x-intercept of the perpendicular line