Question

what is the equation in standard form of a parallel line the passes through (0,-2) use y-3=3(x+1) to get answer

Answer 1

parallel line has the same slope
get the y-3=3(x+1) in to y = mx+b
m is the slope
then
use this y-y1 = m(x-x1) and plug in the points (0,-2) , (x1,y2)

Answer 2

so
y+2 = 3(x-0)
y = 3x-2 ---> slope intercept form

-3x+y = -2----> standard form

Answer 3

are you still stuck on this?

Answer 4

yes im trying to see how you got all the answer I have to show my work O///O