Question

find complex zeros

x^3-1

Answer 1

graph it and see when the line encounter the x axis.

Answer 2

\[x^3-1=0\]\[x^3-1\color{red} {^3}=0\]\[\color{red} {a^3-b^3}=\color{red} {(a-b)(a^2+ab+b^2)}\]\[\color{red} {x^3-1^3}=\color{red} {(x-1)(x^2+x+1)}\]\[\color{rblack} {(x-1)(x^2+x+1)}=0\]

Answer 3

Solve for x.

Answer 4

\[x-1=0~~~~~x=1~~~~OR,\]

Answer 5

\[x^2+x+1=0\]\[\color{black}{\frac{1±i \sqrt{3}}{2}}\]\[\color{blue}{1}~~~,~~~\color{blue}{\frac{1+i \sqrt{3}}{2}}~~~and~~~\color{blue} {\frac{1-i \sqrt{3}}{2}}~~~\]are the zeros

Answer 6

since the last 2 zeros are imaginary the graph would look like just x=1.

Answer 7

solve for x