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How do you simplify 9/3-square root of 2?
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1.58578643763 does this say anything
lol
No, it has to be in a fraction..
These are my choices. I don't want the answer, but could you explain to me how to get the answer?
\[\frac{9}{3}-\sqrt{2}\]\[3-\sqrt{2}\]
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I think we misunderstood the question can you retype it? here is the latex for equation-editor use. \frac{ }{ } fill in the empty spaces in brackets (in equation editor)
for square rot use sqrt{ }
\[\frac{9}{3-\sqrt{2}}\color{blue} {\times \frac{3+\sqrt{2}}{3+\sqrt{2}}}\]
\[\frac{27+9\sqrt{2}}{7}\]
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B
Oh okay! That makes sense. Thank you very much!!
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