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Simplify: (2x^2 y^4)^3 -8x5y7 -6x6y12 none of the above -6x5y7
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Use the rule \[\huge (x^m)^n = x^{n*m}\]
Simplify: (2x^2 y^4)^3 A.-8x5y7 B.-6x6y12 C.none of the above D.-6x5y7
Take everything in the parentheses to the power of 3.
\[\huge 2^3 x^{2*3}y^{4*3}\]
Use this: \[\left( x^{2}*y^{3} \right)^{k} = \left( x^{2*k}*y^{3*k} \right)\]
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so its none of these?
ok, simplify shamil98's response by multiplying the exponents and finding the 2^3
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