Question

y=x^2+6x-2

Answer 1

What do you want to do with the equation?

Answer 2

solve for x?

Answer 3

to use quadratic formula to find the x intercepts. i don't get how to do it at all.

Answer 4

do you know what the quadratic formula is?

Answer 5

have a super slight idea of the concept.
that's all

Answer 6

Umm, we need more info. What's the value of y?

Answer 7

For ax2 + bx + c = 0, the value of x is given by: the formula... x=-b(+-)sqrt(b^2-4ac)/2a

you need y values

Answer 8

well that's all the info i got on my question.

Answer 9

you have b and c

Answer 10

nevermind you dont need y values

Answer 11

no?

Answer 12

your equation looks like this ax2 + bx + c = 0, what you need to do is identify what your c and b is in your equation

Answer 13

and then once that is done, you can plug it into the quadratic equation, which looks like this x=-b(+-)sqrt(b^2-4ac)/2a

Answer 14

ok so like 6x would b and c is -2?

Answer 15

close, sorry you need an "a" value as well. Your A would be 1, b would be 6 and c is -2.

Answer 16

oh i see.

Answer 17

The quadratic equation looks like this x=-b(+-)sqrt(b^2-4ac)/2a, can you try plugging in the values?

Answer 18

the x intercepts is when y =0
so all you are doing is solving the equation for zero

Answer 19

so i just set it all to equal to 0

Answer 20

you can set it equal to x since thats what youre trying to find.

Answer 21

oh yea what he said

Answer 22

thats accurate, you can set it equal to zero and just solve for x

Answer 23

x=-6+sqrt 6^2-4(1)(-2)/2(1) would it look like that

Answer 24

or am i really wrong?

Answer 25

Thats correct, except after the -6 it should be the plus or minus symbol. Now all you need to do is Solve for X. do the things inside the squareroot first

Answer 26

would it be 22?

Answer 27

or i mean 4.69? I am not sure i did that the right way.

Answer 28

i got 3(+-) sqrt(11)

Answer 29

i see what i did wrong..

Answer 30

ok good!

Answer 31

Is this all?

Answer 32

for now thank you. (:

Answer 33

medal? :D