Question

Algebra

Answer 1

@phi

Answer 2

@Victoria_Davis_2018

Answer 3

they say
\[ f(t) = -16t^2 +26t\]
can you find its maximum ? Notice it is a parabola, and the max will be at its vertex.

Answer 4

the max is near 10

Answer 5

Can you find the vertex of
\[ f(t)=−16t^2+26t \]
using
http://www.mathwarehouse.com/geometry/parabola/vertex-of-a-parabola.php

Answer 6

use t (at the vertex) = -b/(2a)
where a is the number in front of the t^2 and b is the number in front of the t

Answer 7

−0.307692307692

Answer 8

what did you use for a and b ?

Answer 9

-16 and 26

Answer 10

yes a= -16 and b is 26
-b/(2a) is -26/-32 = ?

Answer 11

0.8125

Answer 12

to the vertex of f(t) occurs at t= 0.8125
they want the value of f(0.8125)
can you find it ?

Answer 13

no...sorry :/

Answer 14

the equation for f(t) tells you how to do it:
replace the "t" with 0.8125, and simplify

In other words
\[ -16 \cdot 0.8125^2 +26\cdot 0.8125 \]
you need a calculator (or lots of time with pencil and paper)

Answer 15

10.5625

Answer 16

so that is the highest that the dog jumped in inches.
now you need the the max height that the fox jumped. Look at the table and pull out the biggest number.

Answer 17

That will be the answer to part A.

Answer 18

6.24

Answer 19

to what u said before

Answer 20

yes, dog jumped up 10.5625 inches, and the fox jumped to a max of 6.24 inches
I guess you can say the dog jumped higher than the fox.

Answer 21

what about part B and C

Answer 22

@phi

Answer 23

You are supposed to figure out the x intercepts for f(x) and g(x)
the x-intercept is the x number when y is 0

Answer 24

In these, both f(x) and g(x) have 2 x-intercepts.

Answer 25

to be more clear, y is either g(x) or h(x)
the x-intercept of f(x) is the x number when f(x) is 0
the x-intercept of g(x) is the x number when g(x) is 0