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Simplify: t^8/ t^4
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when you divide exponents you subtract them \[\huge \frac{ t^8 }{ t^4 } = t^{8-4}\]
or you could think of it as \[\huge \frac{ t \times t \times t \times t \times t \times t \times t \times t }{ t \times t \times t \times t }\] and cancel the amount of t's in the numerator and denominator
Another rule again, x^a / x^y = x^(a-y) The numerator's exponent - the denominator's exponent. The base has to be the same. so, t^8 / t^4 = t^(8-4) = t^4
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