Question

-3/4<3/8m show work

Answer 1

Is this the question you are asking?

\[-\frac{3}{4} < \frac{3}{8m}\]

m = ?

Answer 2

yes

Answer 3

What have you done so far to solve the problem?

Answer 4

nothing soo confused

Answer 5

math is a hard subject for me i think if i see it in steps ill get it

Answer 6

well do you at least know how to solve a problem like this?

\[-\frac{3}{4} = \frac{3}{8m}\]

Answer 7

3*3=1 4*2=2 so thats 1/2

Answer 8

-1/2

Answer 9

so m<0

Answer 10

Yep thats right. Now we just need to add the inequality back into the problem. Usually the best way to solve this is through the use of a number line:

<------------o----------->
-1/2

The inequality would make the answer be a range of answers, so in order to find this range we must test numbers on both sides of -1/2 to find the answer.

Answer 11

m should either be > -1/2 or < -1/2

Answer 12

m>-1/2 because an inequality goes to the right?

Answer 13

so 1,2,3,4,5,6,7

Answer 14

Thats right, but I'm not sure if you have the correct reasoning down so I'll elaborate further. When we are looking for the answer range for the inequality, we typically test example cases using the number line. For example if m < -1/2, we can choose m = -1 as a test case. Then the equation gives us:

\[-\frac{3}{4} < \frac{3}{8(-1)} ==> -\frac{3}{4} < -\frac{3}{8}\]

which isn't true, so we exclude that m< -1/2 from our answer. When we choose a test case for m > -1/2, lets say m = 1, then we get:

\[-\frac{3}{4} < \frac{3}{8(1)} ==> -\frac{3}{4} < \frac{3}{8}\]

which is true. So we have m > 1/2 as our answer.

The point I'm trying to make is that when you solve inequality problems, you should follow these steps:

1.) Replace the inequality with an equal sign and solve
2.) Put the answers you get from the problem on a number line, and test for each case for each range of possible answers
3.) Combine the range of possible answers into a final answer

Answer 15

err I should say m > -1/2 is our answer. Made a typo

Answer 16

got it thanxs so much

Answer 17

no problem