Question

if x=6sin theta, use trimetric substitution to re write sq rt. 36- x^2

Answer 1

then replace \(x\) by \(6\sin(\theta)\) and see what you get
first step is
\[\sqrt{36-(6\sin(\theta))^2}=\sqrt{36-36\sin^2(\theta)}\]

Answer 2

factor the \(36\) out of the whole thing as
\[6\sqrt{1-\sin^2(\theta)}\] and then use a famous trig identity to rewrite \(1-\sin^2(\theta)=\cos^2(\theta)\) and you are almost done

Answer 3

so its 6 cos theta ?

Answer 4

yes

Answer 5

thanl you

Answer 6

yw