please help. 8x^3+40 + 20+100
Well, you can simplify to 8x^3+ 160
Then take out 8, giving you 8(x^3 + 20)
can you divide the problem by 4 and get 2x^3+10 + 5x+25
Only if it is 20x. Did you mean to say 20x or is it 20?
20x
kirby is like gandhi, trying to bring world peace to math...
Oh okay. Then that changes the problem that I wrote above. ty @trollswillrule
Dear Open Road: I'd suggest you both double check that you've copied the original problem correctly and type the instructions for this problem that you're supposed to follow. As stated, 8x^3+40 + 20+100, is open to several different interpretations. Did you want to simplify the expression? Factor it? Graph it? Best wishes, MM
is it 2x^3+10x^2+5x+25 , it seems highly suspicious like a sandwich without ham or meat
ok. and im guessing after you divide by 4 you factor and get 2x^2(1x+5) + 5(1x+5?
Would hummus be OK? I love it. MM
its 20x everybody
Please, Open Road, type in the original problem again and include instructions.
8x^3+40 + 20x+100 Factor by grouping
are u doing ur assignment on cubic equations? lol no wonder professors are so sad nowadays, hahahaha
im doing a worksheet to freshn up on highschool math before college
8x^3+20x+140=4(2x^3+5x+35), u get a solution of -2.277103687502411 and two imaginary solutions, hence it is not meant to be factorized manually.(use cubic equation)
Dear Open Road: You've typed the expression 8x^3+40 + 20x+100. I suspect that it should be 8x^3 + 40x^2 + 20x +100. I see immediately that 8x^2 can be factored out of the first two terms and 20 out of the last two terms: 8x^2(x+5) + 20(x+5). So (x+5) is the common factor in the above expression. Factoring out the x+5 factor, we get 8x^2+20, or 4(2x^2+5). Thus, the factored form of 8x^3+40 + 20x+100 is (x+5)(4)(2x^2+5). Best wishes, MM
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