“To pass by me you must tell me how to convert standard form into the general, vertex form... I have a test on it next week.”
Explain how to convert f(x) into the general, vertex form of the equation. Use complete sentences. You may use the f(x) you created in question 1 as an example.
my f(x) = x^2 + 10x + 16
do you know how to complete the square ?
That's with using the quadratic formula?
no... its like squaring the half of co-efficient of x
Ok, How would I do that?
f(x) = x^2 + 10x + 16 whats the co-efficient of x ?
10? Because it's before x?
yes
now divide it by 2 and square it what u get ?
25?
yes so add and subtract 25 on right side (x^2+10x +25) + 16-25 did u get what i did ?q
ok... (x^2 + 10x +25) - 9 I don't think I did that right, do I remove the parenthesis?
i kept the paranthesis so that it becomes easy to identify that it is a perfect square trinomial
y = (x+5)^2 - 9
Oh ok, I see where you got that, and this is already the vertex form? Do I have to put the 'a' variable on the outside?
if you need to find 'a' then put 1 outside, because a comes out to be =1 y= a (x-h)^2 +k y= (x+5)^2 -9 a=1 h= -5 k = -9
got it ? y= (x+5)^2-9 is your vertex form :)
Oh! Ok, cool, I understand that!:) Thanks so much! By the way, do you also know with standard form, how I would find the solutions for that? Just a quick question.
whats the standard form ?
ax^2 + bx + c
f(x) = x^2 + 10x + 16 is already in that form a= 1 b=10 c=16
Yes, but would there be a way to find the 'solutions' for that equation?
oh, you need solution for f(x) ?? [but the question didn't ask for it....] so f(x) = 0 x^2+10x +16 =0 know factor method ?
not actually can u tell me 2 numbers whose sum is 10 and product = 16
2 and 8?
yes so x^2+8x +2x +16 =0 know how to proceed ? factor
No, I'm not sure, this would be factoring it out into two sets of parenthesis, right?
Something like (x+8) (x + 2)?
its like this x (x+8) +2 (x+8) = 0 (x+8) (x+2) = 0 x+8 =0 or x+2 = 0 x= -8 or x= -2 thats it!
yes, you were correct :)
Oh, cool! Thanks! You've really helped! And thanks for the medal:)
welcome ^_^
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