Question

The inverse of negative Pi over three? Not entirely sure how to approach this question. Please help?

Answer 1

to me, it's 3/pi

Answer 2

Try that with sqrt(3):
y/x=sqrt(3)
y=x*sqrt(3)

Solve Pythagoras but substituting y:
x² + (x*sqrt(3))² = 1
x² + x² * 3 = 1
4x² = 1
x² = 1/4 => x=1/2, y=sqrt(3)/2

You should then RECOGNIZE the "square root 3 over 2" value as a side of a 30-60-90 triangle in a unit circle. Since y>x, x is positive and arctan is also positive, it is a 60 degree or pi/3 angle

Answer 3

Thank you.