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Mathematics 13 Online
OpenStudy (anonymous):

MEDALS FOR BEST ANSWERS.

OpenStudy (anonymous):

5. How many real number solution does this equation have? y=-4x^2+7x-8 a. no solutions b. one solutions c. two solutions d.infinetely solutions. 6. how many real number solution does this equation have? -8x^2-8x-2=0 a.one solutioin b. two solutions c. no solutions d. infintely many solutions 9. Find the solutions in the system y=x^2-5x+2 y=-6x+4 a. (2,8) and (-1, 2) b. (-2,8) and (1,-2) c. (-2,16) and (1,-2) d. No solutions 10. Find the solutions to the system y=x^2+8x+2 y=7x+4 a. (-2,-10) and (1,11) b. (2,10) and (-1,-11) c. (-2,-34) and (1,11) d. no solutions

OpenStudy (anonymous):

still need help with this or you're okay?

OpenStudy (anonymous):

Still need help!

OpenStudy (anonymous):

@helpme1.2

OpenStudy (anonymous):

the second one has one solution, and the solution is x= -(1/2)

OpenStudy (anonymous):

Okay!

OpenStudy (anonymous):

so 6 has 1 solutions?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

Okay!

OpenStudy (anonymous):

for number 9 and 10, you can use substitution to solve them

OpenStudy (anonymous):

sry, the computer I'm using is acting up brb I need to change a computer

OpenStudy (anonymous):

Okay!

OpenStudy (anonymous):

aright im back

OpenStudy (anonymous):

okay:)

OpenStudy (anonymous):

i cant do 9 or 10. i forgot how to do subsitution

OpenStudy (anonymous):

for #9 use substitution substitute the y y=x^2-5x+2 y=-6x+4 when you sub it, it would be x^2-5x+2=-6x+4 then you can solve for the x in this case, set one side of the equation in to zero x^2-5x+2=-6x+4--->add 6x to both sides, then subtract 4 to both sides x^2+x-2=0 ---> now factor out the problem (x+2)(x-1)=0---> solve for the x's, then you would have x=-2 and x=1 so it has two solutions

OpenStudy (anonymous):

Oh okay, thats where i got stuck is when to solve for x.

OpenStudy (anonymous):

But what would i be? Theres two answers. (-2,8) and (1,-2) and (-2,16) and (1,-2)

OpenStudy (anonymous):

plug the x values in the equation to find y y=-6(1)+4 y=-2---->y value y=-6(-2)+4 y=12+4 y=16---->y value

OpenStudy (anonymous):

Okay! Thanks :) For number 10. i did x^2+8x+2=7x+4 then i subtracted 4 from both sides and got -2. And i subtracted 7x from both sides and got x. So my equation is x^2+x-2. I dont know how to go from there.

OpenStudy (anonymous):

factor out the problem find two numbers when multiplied it gives you -2, and when add gives you 1x

OpenStudy (anonymous):

I dont understand..

OpenStudy (anonymous):

what two numbers gives you -2 when you multiply them?

OpenStudy (anonymous):

-2 *1 = -2 -1*2 = -2 right ? out of those two multiples, when one gives you 1 when added?

OpenStudy (anonymous):

I feel so stupid.. i get when you ask what two number equals -2 but the last question you asked it confusing..

OpenStudy (anonymous):

but you understand now right?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

did you get (x-1)(x+2)=0 when you factored x^2+x-2=0?

OpenStudy (anonymous):

Yes, i couldnt understand the problem.

OpenStudy (anonymous):

now you need to find the x set the each factored form to 0 and solve for x x-1 = 0 x=____ and x+2 = 0 x=___

OpenStudy (anonymous):

1 and 2??

OpenStudy (anonymous):

1 and -2 remember its x+2 = 0---to solve for x, subtract 2 to both sides so it would be x = -2

OpenStudy (anonymous):

Oh yeah. so number 10 is (-2,10) (1,11)?

OpenStudy (anonymous):

no i mean(-2,-10) (1,11)

OpenStudy (anonymous):

correct

OpenStudy (anonymous):

number 5 has only one equation so any number of x gives you y so it has infinity many solutions

OpenStudy (anonymous):

wait so number 5 has one of infinty?

OpenStudy (anonymous):

*or

OpenStudy (anonymous):

And could you help me with a story problem and a 2 other ones?

OpenStudy (anonymous):

@helpme1.2

OpenStudy (anonymous):

number 5 has only one equation so any number of x gives you y so it has infinity many solutions

OpenStudy (anonymous):

Okay!!

OpenStudy (anonymous):

Landon is standing in a hole that is 6.5 ft deep. He throws a rock, and it goes up into the air, out of the hole, and then lands on the ground above. The path of the rock can be modeled by the equation y = -0.05x² + 4.5x – 6.5, where x is the horizontal distance of the rock, in meters, from Landon and y is the height, in meters, of the rock above the ground. How far horizontally from Landon will the rock land? Round your answer to the nearest hundredth of a meter. (1 point) 18.07 m 35.96 m 9.04 m 71.93 m 13. A catapult launches a boulder with an upwark velocity pf 148 feet per second. the heigh of the boulder in feet after t seconds is given by the function h(t)=-16t^2+148t+30. how long does it take the boulder to reach its maximum height? What is the boulders maximum height? a. Reaches a maximum height of 30 feet after 9.25 seconds b. reaches a maximum height of 640.5 feet after 4.63 seconds c. Reaches a maxmum height of 1,056.75 feet after 4.63 seconds d. Reaches a meximum height of 372.25 feet after 4.63 seconds 21. Solve the equation by completeing the square x^2-7x-4=0 a. 7.53, -0.53 b. -7.53, -0.53 c. -7.53, 0.53 d. 7.53, 0.53

OpenStudy (anonymous):

Those are the last questions i need help with. Could you help me?

OpenStudy (anonymous):

@helpme1.2

OpenStudy (anonymous):

i'm not good at word problems, and I don't want to get you wrong in them, but I can help you with #21 completing the square

OpenStudy (anonymous):

okay thats fine

OpenStudy (anonymous):

?

OpenStudy (anonymous):

to complete the square x^2-7x-4 = 0 ---> Move the loose number(4) over to the other side. x^2-7x = 4---> take half of the second x term, and add it to both sides, in this case we take half of 7, which Is 3.5 x^2-7x-3.5 = 4 - 3.5 now convert the left side of the equation to squared form then square root both sides the solve for the problem the answer for your problem would be x = {7.531128874, -0.531128874}

OpenStudy (anonymous):

Thank you so much! you were such a big help :)

OpenStudy (anonymous):

no problem

OpenStudy (anonymous):

i passed! Thanks :)

OpenStudy (anonymous):

yay :)

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