Question

@johnns12234, I can't show the latex and space needed in a msg, so I posted it like this.

Answer 1

1.) Solve each system using substitution. Tell whether the system has one solution, infinitely many solutions, or no solution.
-x + y = -13
3x - y =19

Answer 2

Alright!

Answer 3

-x + y = -13
3x - y =19
------------
(add them) 2x + 0y = 6

2x=6
x=3

Solve for y
-x + y = -13
-(3) + y = -13
-3+y=-13
y=-10

does it work?
-(3) + (-10) = -13 ----> -3-10=-13
3(3) - (-10) =19 ----> 6-(-10)=19 ---> 6+10=19

Answer 4

So yes, there is one solution, and it's extraneous (it works)
x=3 y=-10 or (3,-10)

Answer 5

Thank you so much! I have a couple more wannt help? haha

Answer 6

I have you your medal!

Answer 7

Oh, thank you for the medal.

the main thing is that you get it, and I see you do...

Answer 8

huh?

Answer 9

you would probably nvm me on this one, whatever...

Answer 10

Wait... im so confused

Answer 11

I meant becuase Id get the "huh?" you would probably tell me "nvm"...

Answer 12

okay....?

Answer 13

Yeah, just forget out about it ....

Answer 14

alright...