@johnns12234, I can't show the latex and space needed in a msg, so I posted it like this.

Question

solomonzelman · Answer

1.) Solve each system using substitution. Tell whether the system has one solution, infinitely many solutions, or no solution. 
-x + y = -13  
 3x - y =19

anonymous · Answer

Alright!

solomonzelman · Answer

-x  + y  = -13
                                     3x  - y  =19
                                    ------------
(add them)                      2x + 0y = 6

2x=6
x=3

Solve for y
 -x  + y  = -13
 -(3)  + y  = -13
-3+y=-13
y=-10

does it work?
-(3)  + (-10)  = -13     ---->   -3-10=-13
3(3)  - (-10)  =19         ---->  6-(-10)=19      ---> 6+10=19

solomonzelman · Answer

So yes, there is one solution, and it's extraneous (it works)
x=3 y=-10    or   (3,-10)

anonymous · Answer

Thank you so much! I have a couple more wannt help? haha

anonymous · Answer

I have you your medal!

solomonzelman · Answer

Oh, thank you for the medal.

the main thing is that you get it, and I see you do...

anonymous · Answer

huh?

solomonzelman · Answer

you would probably nvm me on this one, whatever...

anonymous · Answer

Wait... im so confused

solomonzelman · Answer

I meant becuase Id get the "huh?" you would probably tell me "nvm"...

anonymous · Answer

okay....?

solomonzelman · Answer

Yeah, just forget out about it ....

anonymous · Answer

alright...