Question

A 6-kg bowling ball is lifted 2.1m into a storage rack. Calculate the increase in the balls potential energy

Answer 1

The equation you want to use is:
\[V = mgh\]

V is what you need m is them as, h is the distance, and g is the gravitational constant of acceleration: +/-9.8 (depends upon direction, in this case it is lifting up so positive)

So if I am correct then:
\[V = (6kg)(2.1m)(9.8\frac{ m }{ s^2 })\]

Answer 2

Thanks! :)

Answer 3

Welcome!