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Two cars leave Denver at the same time and travel in opposite directions. one car travels 5 mi/h faster then the other car. the cars are 570 mi apart in 6h. how fast is each car traveling?
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570/6=95m/h 95/2=47.5 47.5-5=42.5miles/hr 47.5+5=52.5miles/hr
omg i screwed up again
45 and 50 i believe
Do you know that rate multiplied by time equals distance?
plz disregard what i did with the dividing up there it is suppose to be 95-5=90 90/2=45miles/hr 90-45=50 miles/hr
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Let x = speed of one car then x + 5 = speed of faster car. x + x + 5 = speed of one car relative to the other (they are traveling in opposite direction. Or 2x+5 Now d/s = t 570/(2x + 5) = 6 solving for x: 570= 12x + 30 12x = 540 x= 45 mph x+5 = 50 mph
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