Question

I need some help, please:)

Answer 1

I called 911

Answer 2

\[\frac{ 4p-4 }{ 7 }\times \frac{ 9p ^{2} }{ p ^{2}-p }\]

Answer 3

I don't want the answer,I just want to know how to solve it

Answer 4

Factor p out of the second denominator and than cancel the p with the p^2 in the numerator.

Answer 5

Factor 4 out of the first numerator

Answer 6

okay like this...
\[p ^{2}-p \times \frac{ 4p-4 }{ 7 }\times \frac{ 9p ^{2} }{ p^{2} -p}\times7\]

Answer 7

\[\frac{4(p-1)}{7}\times \frac{9p^2}{p(p-1)}\]

Answer 8

I see,thank you:)

Answer 9

yw

Answer 10

After that it would be
\[\frac{ 4 }{ 7 }\times \frac{ 9p ^{2} }{ p }\] ?