Rodney has fifty coins, including at least one quarter, that are worth $1.00. If he loses one coin, what is the probability that it was a dime?
(A) 0.01 (B) 0.02 (C) 0.04 (D) 0.05 (E) 0.10
@Mertsj
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OpenStudy (calculusxy):
That's what it says in the problem. I imitated whatever it wrote.
OpenStudy (calculusxy):
@satellite73
OpenStudy (calculusxy):
I truly have no idea :/
OpenStudy (calculusxy):
They say that the answer is C but I don't get it.
OpenStudy (mertsj):
Oh. I reread it. They are worth 1.00 so you can figure out the composition of the 50 coins. Work on it until you figure out which 50 coins add up to $100
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OpenStudy (mertsj):
$1.00 not $100
OpenStudy (calculusxy):
That's going to take more than a while.
OpenStudy (calculusxy):
@hartnn
OpenStudy (mertsj):
1 quarter, 2 dimes, 45 pennies, 2 nickels
OpenStudy (mertsj):
Probability of losing a dime = 2/50
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OpenStudy (calculusxy):
Can it be also possible that when you subtract 1.00-.25=.50 then you can think of about 0.5 of 1.00, which can be put as to 0.4