Given two rectangles, one with length = l and width = w, and the second rectangle with length = 2l and width = 4w. How much larger will the perimeter of the second rectangle be than the perimeter of the first rectangle?

Question

theislander · Answer

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bibby · Answer

the first rectangle has a perimeter of 2l + 2w as there are 2 lengths and witdths

the second has a perimeter of 2(2l) + 2(4w)

mathstudent55 · Answer

Do you know how to find the perimeter of a rectangle?

anonymous · Answer

Do an experiment: 
suppose l=2 and w=2 in first rectangle. The perimeter would be 8
in the second rectangle 2(2)(2) + 2(4)(2)=24
The second rectangle is 3 times the size. 
The equation that matches is the 3rd one: P2=2P1+4W