Question

how do you find the slope of the tangent line for:
y^2=x^3/(4-x)

Answer 1

at the point (2,2)

Answer 2

Do implicit differentiation and evaluate y' at (2,2)

Answer 3

Do you take the square root first?

Answer 4

No need to take square root.
y^2=x^3/(4-x)
differentiate both sides:
2yy' = { (4-x)(3x^2) _ x^3(-1) } / (4-x)^2
put x = 2, y = 2 above and solve for y'

Answer 5

Ohhhhh right, okay! Thank you!

Answer 6

you are welcome.