I need help with completing a square.
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y = -2x^2 - 16x + 1
@amistre64 @ranga
Make the x^2 coefficient 1 by factoring out -2: y = -2x^2 - 16x + 1 = -2(x^2 + 8x - 1/2) To complete the square, divide the coefficient of x by 2. 8/2 = +4. This is the number that will go inside the parenthesis with x to be squared. Subtract 4^2. y = -2{ (x + 4)^2 - 4^2 - 1/2 } = -2{ (x + 4)^2 - 16 - 0.5 ) = -2{ (x + 4)^2 - 16.5 } y = -2(x + 4)^2 + 33
and can you help me with another one?
y = x^2 + 4x
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not funny
Follow the same procedure. Divide the coefficient of x by 2: 4/2 = 2. This 2 will go inside the parenthesis to be squared and you will have to subtract 2^2 y = x^2 + 4x y = (x + 2)^2 - 2^2 y = (x + 2)^2 - 4
Ohh.. so y = (x+2)^2 - 4 is the answer? (-2,-4) ? @ranga
If you are asked to find the vertex, then (-2, -4) is the vertex. If you are simply asked to complete the square as stated in the problem, then y = (x + 2)^2 - 4 is the answer.
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