How to factor out the GCF in an equation? 2x^3y + 8xy - 4x^2y - 16y
\[2x^{3}y + 8xy - 4x^{2}y - 16y\] \[y(2x^{3} + 8x - 4x^{2} -16)\]
2 can also be factored out...
yes, true. \[2y(x^{3} + 4x - 2x^{2} - 8)\]
Could you help me with factoring it as well?
first, organize it like this \[2y(x^{3} - 2x^{2} + 4x - 8)\] What next?
(Also thank you for helping the GCF.. That was my original answer, but I was unsure.) Would we multiple everything by 2y?
No, you would want to leave that out. Is there an equals sign in this? I feel like there should be more info...
The instructions: Rewrite the expression completely factored. Show the steps of your work. 2x3y + 8xy - 4x2y - 16y
okay. Then just factor it. Do you know how to factor a quadnomial?
Not at all. I had to miss a week of school do to health reasons.. My teacher told me the best way to learn was to do it on my own.
sorry I have to leave. I'll do it tomorrow if I have time
\[2y(x^{2}(x - 2) + 4(x - 2))\] That's the next step. Can you do the rest?
@becca9898
Would it then be: \[2y(x-2)(x^2+4)\]
Yes! good job @becca9898
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