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Mathematics 16 Online
OpenStudy (anonymous):

Given the triangle and equation below, what is the value of x? csc∠A + tan∠C = 5x fraction 35 plus 5 times the square root of 13 over 6 fraction 7 plus square root of 13 over 30 fraction 7 plus 6 times the square root of 13 over 210 fraction 35 plus 30 times the square root of 13 over 42

OpenStudy (anonymous):

OpenStudy (anonymous):

is x suppose to be the legnth of the side on the left?

OpenStudy (anonymous):

That is part of the reason why I am confused. See, I don't know what x is. I am starting to believe that you have to solve the equation on the bottom in order to get x. However, I am unsure as to how to solve that as well.

OpenStudy (anonymous):

Let A=6 B=? C=7 substitute into the equation: \[A^2 + B^2 = C^2\] solve for B, B will be the value for x, which is the missing side length.

OpenStudy (anonymous):

Yes, B = 3.60. That is how far I got before doing some jibber jabber with csc and tan

OpenStudy (anonymous):

then ur done! that is all you can do, unless they want you to find the angles ..

OpenStudy (anonymous):

wait.. not so..

OpenStudy (anonymous):

Oh. ok. Thanks for your help. :)

OpenStudy (anonymous):

Oh, what's missing?

OpenStudy (anonymous):

csc∠A + tan∠C = 5x 1/sinA + tanC = 5x so we need to find the angle of A.... wait.. how do we know which anlge on the drawing is A?

OpenStudy (anonymous):

The best I can figure is that A is the angle on the top, is that what you think too?

OpenStudy (anonymous):

if so, use the law of sines. do sin90/7 = sinA/6 and solve for A

OpenStudy (anonymous):

I did not realize how poorly the choices came out, this should help

OpenStudy (anonymous):

then we need to solve for C, so do sinC/3.6 = sin90/7 solve for C

OpenStudy (anonymous):

Yeah, I agree with A being angle on top

OpenStudy (anonymous):

we can solve this i think. just do what I said, solve for A and for C using the law of sines

OpenStudy (anonymous):

Sorry, I was having a brainfart. Just to make sure I am back on track, A =58 correct?

OpenStudy (anonymous):

If so, then C = 32

OpenStudy (anonymous):

I really can't say, i don't have a calc with trig near me!

OpenStudy (anonymous):

1/sinA + tanC = 5x 1/sin(58) + tan(32) = 5x solve for x

OpenStudy (anonymous):

Okay, I did SOH 6/7 0.857 sin-1 I got 58 then for C, I took 180-90-58=32

OpenStudy (anonymous):

oh, smart move for finding C

OpenStudy (anonymous):

Thanks :)

OpenStudy (anonymous):

I got an answer for x using your method(thanks by the way) however, the answer choices for the question are in the how to solve for it, so naturally, I looked for what we did as a choice, but no luck.

OpenStudy (anonymous):

what did you get for the value of x?

OpenStudy (anonymous):

have you gone through each choice and converted it to a decimal number and then check it witht he value of X you solved for?

OpenStudy (anonymous):

I got 1.796 for x

OpenStudy (anonymous):

Ugh, I thought the answer choices were asking for how to solve it, my bad. I will check now

OpenStudy (anonymous):

^_^

OpenStudy (radar):

Use the figure and calculate angle C. It is a right triangle and Cos C=6/7 thus angle C is 31 degrees (inverse cos function) The remaining angle is 90-31 or 59 degrees. That would be angle A.

OpenStudy (anonymous):

I believe it is A because the answer to A is only a few points off, so it could be from rounding.

OpenStudy (anonymous):

Another reason for my answer possibly being off could be in the angles, because radar, you got 1 off from mine. I am sure mine are wrong, so I am going to go with answer choice A unless if one of you disagree.

OpenStudy (radar):

Now use a calculator and calculate Csc 59 degrees. Csc 59= 1/sin 59 = 1.1666 Now calculate Tan 31 degrees which is 0.600. The equation provided in the problem substituting values obtained: 1.16666 + .600 = 5x 1.7675 = 5x x=0.3535 Seems like a strange answer, possibly I strayed from the correct path.

OpenStudy (anonymous):

No, you are right! I accidentally made a mistake and thought my answer as being x, multiplying it by 5... Which makes B correct, as it is spot on. Thanks :)

OpenStudy (anonymous):

And demolisionwolf, thanks for helping me out a lot also, as for you to radar, you guys have a good night.|dw:1387420880779:dw|

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