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OpenStudy (anonymous):
Q) e^2y + xy = 4x + 1. find dy/dx and
equation of the tangent to the curve.
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OpenStudy (isaiah.feynman):
At what point?
OpenStudy (anonymous):
the origin.
OpenStudy (isaiah.feynman):
(0,0). Differentiate the function implicitly. Then evaluate it at (0,0).
OpenStudy (anonymous):
Can anyone help with differentiating the function?
OpenStudy (isaiah.feynman):
Not quite.
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OpenStudy (anonymous):
Ok my latest attempt I get:
dy/dx = 4 - y / e^(2y) + x
I hope that's correct?
OpenStudy (isaiah.feynman):
Yes, but you are missing a 2 in front of e.
OpenStudy (anonymous):
Yep - sorry typo. Finally - hooray! Now for the next part of the Qu.
OpenStudy (isaiah.feynman):
Simply substitute, 0 for x and y and see the outcome. Well the outcome will be the slope.
OpenStudy (isaiah.feynman):
Of that line.
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OpenStudy (anonymous):
That gives me 4/3.
OpenStudy (isaiah.feynman):
Where would 3 come from??
OpenStudy (anonymous):
oops sorry, 4/2 = 2...
OpenStudy (isaiah.feynman):
That's the SLOPE of that line. Remember how to find the equation of a line when you have the slope and point? From algebra classes in high school.
OpenStudy (anonymous):
Yep the equation part is fine. Thanks.
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OpenStudy (isaiah.feynman):
Good good.
OpenStudy (anonymous):
y-0=2(x-0)
y=2x
OpenStudy (isaiah.feynman):
Nice.
OpenStudy (anonymous):
Thanks.
OpenStudy (isaiah.feynman):
Welcome.
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