Question

Please help with these two functions, I have to solve for x
-2=log(3x+5)

and

e^x e^(x+1)=1

Thank you!!!

Answer 1

you're welcome

Answer 2

Use the rule:
\[\huge \log_a x = n ---> x = a^n\]
Treat (3x+5) as a variable.
if there is no base log there, we assume it has the base of 10.
so
\[\huge \log_{10}(3x+5) = -2\]
Use the given rule above and do it from there :)

Answer 3

Shami is on the right track. The principle here is that y = (log to the base a of x) and y = a^x are INVERSE FUNCTIONS.

Thus, 3 raised to the power (log to the base a of x) results in just x.

Next, 3 raised to the power -2 results in what numerical value?

Write the solution: x = 3^(-2).

Apply the same procedure to solve Emmm's original question.